x^2+2y^2-8x+4y=t

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Solution for x^2+2y^2-8x+4y=t equation:


Simplifying
x2 + 2y2 + -8x + 4y = t

Reorder the terms:
-8x + x2 + 4y + 2y2 = t

Solving
-8x + x2 + 4y + 2y2 = t

Solving for variable 'x'.

Reorder the terms:
-1t + -8x + x2 + 4y + 2y2 = t + -1t

Combine like terms: t + -1t = 0
-1t + -8x + x2 + 4y + 2y2 = 0

The solution to this equation could not be determined.

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